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Re: Topband: Broadband Inverted L

To: topband@contesting.com
Subject: Re: Topband: Broadband Inverted L
From: Jim Brown <jim@audiosystemsgroup.com>
Reply-to: jim@audiosystemsgroup.com
Date: Thu, 20 Nov 2014 11:52:28 -0800
List-post: <topband@contesting.com">mailto:topband@contesting.com>
On Thu,11/20/2014 11:17 AM, Tom W8JI wrote:
Joe's antenna virtually doesn't have a ground connection to radials at all, and this has almost nothing to do with the number of radials or type of radials.

Yes, but there's another important concept that is being missed here. The function of a radial system is NOT to couple the antenna to the earth, it is to SHIELD the antenna from the earth. Rather, the function of a radial system is to serve as a return for both the antenna current AND THE FIELD produced by the antenna. That is, a good radial system acts as a SHIELD between that field and the lossy earth. Joe's system has a counterpoise (a return for the current), albeit not a good one, but it doesn't perform the shielding function because it's not just below the base of the antenna.

K2AV's folded counterpoise is another example of a system that provides an effective return for antenna current, but provides much less of a shielding function.

>

Time to go out and connect more radials directly to the
feed point ground.

NOT to the earth, to the coax shield.

I can also elevate two of them.

I suggest that you study the link I posted. N6LF has done a lot of excellent 
work on radial systems, much of which is summarized in that link.

On 160M, radials must be at least 16 ft off the ground to work as "elevated 
radials," and they should be of equal lengths and heights. Radials on the ground can 
be of any length --the only more or less universal rules of thumb is that more copper on 
the ground is better, and more short radials is better than a few long ones.

Think of it this way -- the current in any radial must be minimum at the end, 
and if it's less than a quarter wave, will be maximum at the feedpoint. The 
antenna return current divides between the radials, and the loss is I squared 
R, where this R is coupled from the lossy earth. The more radials there are to 
divide that current, the less will be the lost power! That's because the 
current is divided by N (the number of radials) while the loss is divided by N 
squared.

The reason a fewer number of elevated radials can work as well as many more on 
the ground is that the fields from the elevated radials don't couple as closely 
to the earth, so there's less coupled R, and thus less lost power.

73, Jim K9YC

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