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Re: [TowerTalk] Connector Loss Question

To: N7KA@comcast.net
Subject: Re: [TowerTalk] Connector Loss Question
From: jimlux <jimlux@earthlink.net>
Date: Tue, 26 Aug 2008 06:20:47 -0700
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
N7KA@comcast.net wrote:
> Here is some differnt info.
> 
> http://www.amphenolrf.com/products/typen.asp?N=0&sid=48B3478041F8E17F

That data (0.15 dB @ 10 GHz) implies that the K in Joe's equation should 
be a bit less than 0.05, rather than 0.5

>>
>>
>> Joe Reisert, W1JR wrote: 
>>> Hi Manius, 
>>>
>>> The insertion loss of a good N connector is equal to the square root 
>>> of F (in GHz) times a constant (K). 
>>>
>>> The constant for a single N connector is 0.5. Therefore, at 23 CM 
>>> (1.3 GHz) the loss is approximately .057 dB so you can add up the 
>>> losses based on your situation. 

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