Joe,
Sorry to "nit pick", but if your formula is correct and the constant is
0.5, shouldn't the loss be 0.57dB? It makes a big difference if you have
several connectors in the chain.
73,
Steve G3TXQ
Joe Reisert, W1JR wrote:
> Hi Manius,
>
> The insertion loss of a good N connector is equal to the square root
> of F (in GHz) times a constant (K).
>
> The constant for a single N connector is 0.5. Therefore, at 23 CM
> (1.3 GHz) the loss is approximately .057 dB so you can add up the
> losses based on your situation.
>
> 73,
>
> Joe, W1JR
>
>
>
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