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Re: [TowerTalk] Connector Loss Question

To: towertalk@contesting.com
Subject: Re: [TowerTalk] Connector Loss Question
From: Steve Hunt <steve@karinya.net>
Date: Tue, 26 Aug 2008 11:50:12 +0100
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
Joe,

Sorry to "nit pick", but if your formula is correct and the constant is 
0.5, shouldn't the loss be 0.57dB? It makes a big difference if you have 
several connectors in the chain.

73,
Steve G3TXQ


Joe Reisert, W1JR wrote:
> Hi Manius,
>
> The insertion loss of a good N connector is equal to the square root 
> of F (in GHz) times a constant (K).
>
> The constant for a single N connector is 0.5. Therefore, at 23 CM 
> (1.3 GHz) the loss is approximately .057 dB so you can add up the 
> losses based on your situation.
>
> 73,
>
> Joe, W1JR
>
>   
>

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