We are trying to match 50 ohms to the tube plate under full power output
conditions for the class of operation. Full power output happens with full
drive, maximum plate current and whatever plate voltage is present under these
conditions. Therefore, the voltage to be used is the full load value which is
invariably less than no load conditions due to power supply and ac line voltage
IR drop.
73,
Gerald K5GW
In a message dated 3/31/2006 10:22:21 A.M. Central Standard Time,
gpatterson53@hotmail.com writes:
ok.... one guy says use the "open circuit voltage" the other guy say use the
loaded "operating voltage" ..................who is correct
>From: "Phil Clements" <philc@texascellnet.com>
>To: "'Partain, Chuck'" <Chuck_Partain@maxtor.com>,<amps@contesting.com>
>Subject: Re: [Amps] tube impedance, figuring tank circuit values
>Date: Thu, 30 Mar 2006 16:20:27 -0600
>
>
> >
> > So, when I power up my amp, I see 3910vdc on my plate. The way I have it
> > configured, I put 330vdc on the screen grid
> > and -130volts on the control grid., when I bring the control grid to
>-69v,
> > the tube pulls current. The voltage on the plate is
> > dropping to ~3600 to 3700. Is this the value I would use to figure the
> > impedance of the tube for tank calculations?
>
>
>No, the voltage and current of the amp when it is running at what you plan
>to operate it at are the values that you plug into the formula. Say that
>the
>voltage drops to 3500 volts at an operating anode current of 1 amp; your
>tank should be configured for that, not the resting anode I.
>
>(((73)))
>Phil, K5PC
>
>
>
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