Reference the thread about this: The PIV across each diode in a bridge will be
the peak voltage of the transformer voltage. . . . . , I offer some words of
caution:
How the reverse voltage disributes across a chain of diodes is problematic in a
way that is similar to the way power supply output voltage distributes across a
chain of filter capacitors. One of the important functions that bleeder
resistors serve across such a string of capacitors is to equalize the voltage
drops. Just as electrolytic filter capacitors vary A LOT in how much they
"leak" current, meaning how much they vary as resistors across the output
voltage, rectifier diodes vary considerably in how much they leak when they are
reverse biased. Once when I had access to the instruments that I could do this
with, I got a batch of about 200 1 KV PIV diodes, reverse biased them to about
800V and measured the currents through them. The currents varied from several
microramperes to a mil or so, easily a ratio of 20:1 or more. This is the
reason that you see resistors of about 470K-ohms to about a megohm across a
chain of diodes -- to "swamp" the leakage and equalize the voltage dr
ops when they are reverse biased. I put about a megohm across each diode in a
chain or leg of diodes, and use enough diodes to give a total PIV of 5X the
output voltage. Nothing blows. I concede that I am conservative here, but
diodes and resistors are cheap.
Gene May
WB8WKU
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