Let's see ....
E=IR ... so the voltage loss in the secondary would be
E= 147 x current drawn .... say 2 amps = 294volts
5200 - 294 = 4906 volts.....
Why do you think you won't get much current out of the transformer?
Or is my calculation 'fuzzy'?
73
Don
N8DE
Quoting Gary Patterson <gpatterson53@hotmail.com>:
>
>
> I picked up a large maybe 70-80 pound transformer that has only a
> 115 primary. I measured secondary voltage at about 5200 v. The
> secondary resistance is 147 ohms. Am I correct in assuming I wont
> get much current out of this??
> GaryW4AF
>
>
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