To: | <amps@contesting.com> |
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Subject: | [AMPS] Diodes |
From: | 2@vc.net (measures) |
Date: | Wed, 23 Feb 2000 08:51:35 -0700 |
> >Rich says: > >>Without equalization, the 250v reverse surge happily divides unequally. >>Approx. 101v is dropped acrosss the 101v diode and approx. 149v is >>dropped across the 190v diode. > >Not if the diode capacities are equal. the resistance of the equalizers is not a factor? >Two equal diode capacities will >attempt to split the voltage equally. The probability is that they aren't >equal, though. A safe wager. . . >Frequency has nothing to do with it, The 10k-ohm "equalizer" resistances seem to be in the driver's seat. >since voltage division >across series capacitors is in the ratio of the capacities - even at DC. > cheers, Peter -- FAQ on WWW: http://www.contesting.com/ampsfaq.html Submissions: amps@contesting.com Administrative requests: amps-REQUEST@contesting.com Problems: owner-amps@contesting.com Search: http://www.contesting.com/km9p/search.htm |
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