Hi,
I'm not so experianced this 3 phase transformers and have the following
questions:
I have a 3 phase transformer which has on the secundar 3 coils of about
810VAC. If I take a normal diode bridge I will have Us=810V x squrt 2 x sqrt
3 = 1980V. Actually I'm looking for a voltage in the area close to 4000VDC
or at least closer to 2500VDC. Is there a methode to reach this goal?
I saw a drawing for a 1 phase transformer with 2 diodes and 2 C's to double
the voltage. One coil was conected between the C's and the other side of the
coil was connected to the diodes. The diodes were connectet in such a way
that the positive wave went to the upper C and the negative wave went to the
lower C. So you can use the formular Us= 810V x sqrt 2 x 2 = 2290V.
Does this methode work with 3 phases in the same way?
Thanks for your help in advance and hope to catch you on the band
Oliver, DL1EJA
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