In einer eMail vom 15.04.03 08:23:42 (MEZ) - Mitteleurop. Sommerzeit schreibt
DL1EJA@yahoo.de:
> I saw a drawing for a 1 phase transformer with 2 diodes and 2 C's to double
> the voltage. One coil was conected between the C's and the other side of the
> coil was connected to the diodes. The diodes were connectet in such a way
> that the positive wave went to the upper C and the negative wave went to the
> lower C. So you can use the formular Us= 810V x sqrt 2 x 2 = 2290V.
>
> Does this methode work with 3 phases in the same way?
>
Hi Oliver
That will work for you when you use the star-circuit.
About 30 years ago I used linears with sweep-tubes PL519 and a
3-phase transformerless power-supply with possible output voltage
up to 1800V.
This was done by switchable oneway/doubler/tripler rectifier-circuits
for positive and negative voltages.
The total amount of capacitors used were 120 millifarads!
This was a very stiff supply, for instance no load voltage by
using the doubler for +600 and oneway-rectifier for -300 was 930V,
which dropped to 910V only at 10A...
73
Peter
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