Voltage at dipole tips — it’s a kind of interesting question.
I was thinking of putting a dipole in a stand of aspen trees which I do NOT
want to burn down. There is no way to route the wires to completely avoid
contact with the twig-like upper branches. And, I do run full power.
I did find some high voltage wire by Gore that is rated at 13 KV although I’m
not sure that was at RF — might have been DC. It is insulated with PTFE.
Looked interesting..
The idea of looking at the feed point impedance of a 1 wavelength doublet for a
first order approximation is a good one. I may try modeling that, just to
bring closure to my idea..
73,
Doug, W7KF
> On Mar 31, 2017, at 2:39 PM, jimlux <jimlux@earthlink.net> wrote:
>
> On 3/31/17 12:25 PM, Jim Thomson wrote:
>> Ok, the peak V on the tips of a dipole is sky high. But what about the
>> polarity between
>> the ends ? If one end is + 10 kv, is the other end at – 10 kv ?? Is
>> there a 20 kv
>> potential difference between them at all times ?
>>
>
> It's very hard to calculate (or measure) the actual voltage at the ends -
> best you can say is "it's high". You can infer a voltage by calculating the
> feedpoint impedance of a 1 wavelength long doublet, then putting in 2x power
> (each half radiates full power), and using Ohms law.
>
>
> Yes, it would be opposite polarity. but not "at all times" because it goes
> through zero every half cycle.
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