Hi Gary-
I found this link from K7NV
<http://k7nv.com/notebook/topics/windload.html>. Hopefully, this will
help. I would assume you would do a force calculation for each diameter
piece and add the forces up of all the different pieces.
Dick, K0CAT
=============================
Gary Smith wrote on 8/30/2016 2:20 PM:
I'm having to play games with setting up eight, short, active
vertical elements on an incredibly rocky area. I am not able to drive
in ground rods, much less the base of the antennas. I'm coming up
with a plan to make wooden bases for them and hold them down with
rocks.
Since I live on the ocean's edge and have to contend with hurricane
force winds every so often, I'm trying to figure out the wind loading
of the verticals I'm considering. I'll buy the aluminum sections from
DXE and prefer to use larger sections just because of branches
falling at the marsh edge, as they always do. But thicker pieces will
have more wind loading and that is a problem.
If I use the thinnest configuration I'll have about 22 feet tall made
of .375, .5, .625 & .750 sections.
I asked what the wind loading would be and nobody I talked to was
able to give me a clue. Does anyone know a formula to figure the wind
loading of tapered elements?
Thanks & 73,
Gary
KA1J
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