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Re: [TowerTalk] TowerTalk Inverted vee

To: <towertalk@contesting.com>
Subject: Re: [TowerTalk] TowerTalk Inverted vee
From: "Earl Morse" <kz8e@wtd.net>
Reply-to: kz8e@wtd.net
Date: Thu, 22 Oct 2015 15:05:05 -0700
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
This will get you close.

If 

468/3.615 = 129.46'

and 

468/3.515 = 133.14'

Then 133.14 - 129.46 = 3.68' or 1.84' (1' 10") per leg.

Now if you know how long the dipole is that is up there now you could 
recalclate the 468 constant and work the equation with the new constant to get 
the exact new dimension.

Then there is try try again if you don't get it right the first time.

Earl
N8SS



--- towertalk-request@contesting.com wrote:

------------------------------

Message: 4
Date: Thu, 22 Oct 2015 17:21:33 -0400
From: "Carol Richards" <n2mm@comcast.net>
To: <towertalk@contesting.com>
Subject: [TowerTalk] Inverted vee
Message-ID: <9C2AF02170D74D59BDD99962BDF488B0@HPDesktop>
Content-Type: text/plain; format=flowed; charset="iso-8859-1";
        reply-type=original

Hello,


I have an inverted vee up about 100 feet. It resonates at 3615. From past 
experience, how much should I add to each leg to get it down to 3515?


Thanks,


Carol 



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