If you know the diameter of the element you can make a first order
approximation. Multiply the diameter (in inches) by the length (in inches) for
square inches, then divide by 144 for square feet. That's actually worse than
the real wind load, as it assumes no streamlining benefit from tubular elements.
A 1 inch diameter element 17 feet long would calculate out to 1.4 sq feet of
wind load using the above. The real wind load is certainly less than that.
Al
AB2ZY
________________________________________
From: towertalk-bounces@contesting.com [towertalk-bounces@contesting.com] On
Behalf Of Mario [marionow@gmail.com]
Sent: Friday, July 27, 2012 11:14 AM
To: towertalk@contesting.com
Subject: [TowerTalk] VHF/UHF verticals wind load
I'm going to install in the near future a dual band VHF/UHF Diamond X510HDN,
this antenna has over 17ft? Does anyone know what would be the wind load?
I've checked the manufacturer website and searched Google but found nothing
about that.
Thanks
Mario
KC8P
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