> I *think* this is what I was asking originally. If I add capacitance
> and Z decreases, doesn't that mean that the initial X was inductive,
> and the capacitance has cancelled some of it out? Does it not then
> follow that if I continue to add C at a given frequency until Z stops
> decreasing and begins to increase again, I've probably located X=0 and
> therefore Z=R? Under what circumstances does X change sign without
> passing through 0?
That's true. If you leave it sit on one frequency and change
capacitance, minimum Z (assuming it goe through a minimum) is
resonance and Z=R.
73, Tom W8JI
W8JI@contesting.com
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