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[TowerTalk] Re: Optimum Stacking Distance

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Subject: [TowerTalk] Re: Optimum Stacking Distance
From: Jan.E.Holm@telia.se (Jan.E.Holm@telia.se)
Date: Sat, 28 Jul 2001 10:16:13 +0200
Yes, as SM2CEW points out these formulas are overruled
these days, this stuff is probably 20 years old by now.
However, using these formulas might not produce a 100%
optimum array but I dont think it will be far off but
for EME when you are hunting tens of dB´s it might not
apply any more.

de SM2EKM


> 
> Formula you are looking for might be:
> 
>         y
>   X=  --------
>       2sin(Z/2)
> 
> where   X= optimal stacking distance
>         Y= lambda (boom lenght)
>         Z= 3 dB beamwith angle
> 
> This is from work by DL6WU
> 
> This is alo used
> 
> Stacking dist=   57.3
>                -------------------
>                 3 dB beamwith / 2  
> 
> This is for VHF/UHF stacking for optimum pattern EME arrays.
> Will give very clean pattern with low sideloobs, i e the
> array will have very good G/T.
> 
> I hope I didn´t mess these formulas up but I think this
> might be what KQ2M was thinking about, in any case I dont
> think it does add anything important to this subject.
> 
> 73, Jim SM2EKM
> ------------------------------------------------------------
> However, this doesnt apply for HF stacking where we
> are looking for other things.
> 
> 
> > 
> > 
> > Some advice to take the effective boom length of the antenna in 
> > wavelengths
> > and take the square root of it.  This is the optimum stacking 
> > distance of
> > your beams in Wavelength.
> > 
> > I think it is way too general not taking into account heights and 
> > antenna
> > specifications.
> > 
> > You can only find the answer with modelling software.
> > 
> > Tonno
> > ES5TV
> > 
> > ----- Original Message -----
> > From: "Robert Shohet" <kq2m@mags.net>
> > To: <towertalk@contesting.com>
> > Sent: Friday, July 27, 2001 8:47 PM
> > Subject: [TowerTalk] Optimum Stacking Distance
> > 
> > 
> > >
> > > I have been told that there is a formula for the optimum 
stacking 
> > > distance
> > > of similar antennas that is based on the antenna boom lengths 
and 
> > > other
> > > factors.
> > >
> > > If anyone is familiar with this, could they please post the 
> > >formula?
> > >
> > > Tnx & 73
> > >
> > > Bob KQ2M
> > >
> > >
> > >
> > >
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> > 
> > 
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> 
> 
> 
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