>>Ah ... a cubic yard is 3 x 3 x 3 or 27 cubic feet.
>>27*.67= 18.09 cubic feet required (using your figure)
>>18.09/3.14=5.76 feet depth required for 1 foot diameter;
>>18.09/6.28=2.88 feet depth required for 2 foot diameter.
>
>Hmm. My back of the envelope computation says something isn't right. If
>you double the diameter, that quadruples the volume per foot of height.
>If 5.76 feet is right for a 1 foot hole, then a two foot hole should
>require 1/4 of that, or roughly 1.5 feet, less about an inch or so.
>
>The volume should be 2*pi*h*r**2.
Well, maybe it should be, but it isn't.
Let's try pi*r^2*h (no 2* in there)
Area of a circle is pi*r^2, times the height is volume.
>>Not sure whether I'd try to second guess the engineering.
>
>Certainly not with math like that. <grin>
Nor with that math. :)
p.s. a 1 foot diameter hole would need to be 23 feet deep to equal 18 ft^3
a 2 foot diameter hole would need to be 5.76' deep to equal 18 ft^3
---
Chad Kurszewski, WE9V e-mail: Chad_Kurszewski@csg.mot.com
The Official "Sultans of Shwing" Web Site: http://www.QTH.com/sos
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