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Topband: Flag theory by Dr Dallas

To: CUTTER DAVID via Topband <topband@contesting.com>
Subject: Topband: Flag theory by Dr Dallas
From: Jose_Carlos <N4IS@COMCAST.NET>
Date: Fri, 26 Feb 2021 11:13:21 -0500
List-post: <mailto:topband@contesting.com>
Hi guys


I would like to share some papers from my good friend (SK) Dr Dallas was a 
great experimental guy that loved Mathematic and AM DXing,. Dr Dallas with a 
strong personality and seniority some times was hard to follow and some time 
the result of tests were not as planned, like the multi turn flags.

Dr Dallas interest was on MF 500KHz to 1600 MHz  and some results are not the 
same on 160 or 80m. I can send the original paper attached if requested.


 Flag Theory
Dallas Lankford, 1/31/09, rev. 9/9/09
The derivation which follows is a variation of Belrose's classical derivation 
for ferrite rod loop antennas,
“Ferromagnetic Loop Aerials,” Wireless Engineer, February 1955, 41– 46.
Some people who have not actually compared the signal output of a flag antenna 
to other small antennas have
expressed their opinions to me that the signal output of a flag antenna has 
great attenuation compared to those
other small antennas, such as loops and passive verticals. Their opinions are 
wrong. One should never express
opinions which are based, say, on computer simulations alone, without actual 
measurements. The development
below is based on physics (including Maxwell's equations), mathematics, and 
measurements.
Measurements have confirmed that the flag signal to noise formula derived below 
is approximately correct
despite EZNEC simulations to the contrary. For example, EZNEC simulation of a 
15' square loop at 1 MHz
predicts its gain is about +4 dbi, while on the other hand EZNEC simulation of 
a 15' square flag at 1 MHz
predicts its gain is about –46 dBi. But if you construct such a loop and such a 
flag and observe the signal
strengths produced by them for daytime groundwave MW signals, you will find 
that the maximum loop and flag
signal outputs are about equal. Although somewhat more difficult to judge, the 
nighttime skywave MW signals
are also about equal.
Also, the signal to noise ratio formula below for flag arrays has been verified 
by man made noise measurements
in the 160 meter band using a smaller flag array than the MW flag array 
discussed below. Several years ago a
similar signal to noise ratio formula for small untuned (broadband) loop 
antennas was verified at the low end of
the NDB band.
The signal voltage es in volts for a one turn loop of area A in meters and a 
signal of wavelength λ for a given
radio wave is
es = [2πA Es /λ] COS(θ)
where Es is the signal strength in volts per meter and θ is the angle between 
the plane of the loop and the radio
wave. It is well known that if an omnidirectional antenna, say a short whip, is 
attached to one of the output
terminals of the loop and the phase difference between the loop and vertical 
and the amplitude of the whip are
adjusted to produce a cardioid patten, then this occurs for a phase difference 
of 90 degrees and a whip amplitude
equal to the amplitude of the loop, and the signal voltage in this case is
es = [2πA Es /λ] [1 + COS(θ)] .
Notice that the maximum signal voltage of the cardioid antenna is twice the 
maximum signal voltage of the loop
(or vertical) alone. A flag antenna is a one turn loop antenna with a 
resistance of several hundred ohms inserted
at some point into the one turn. With a rectangular turn, with the resistor 
appropriately placed and adjusted for
the appropriate value, the flag antenna will generate a cardioid pattern. The 
exact mechanism by which this
occurs is not given here. Nevertheless, based on measurements, the flag antenna 
signal voltage is approximately
the same as the cardioid pattern given above. The difference between an actual 
flag and the cardioid pattern
above is that an actual flag pattern is not a perfect cardioid for some 
cardioid geometries and resistors. In
general a flag pattern will be
es = [2πA Es /λ] [1 + kCOS(θ)]
where k is a constant less than or equal to 1, say 0.90 for a “poor” flag, to 
0.99 or more for a “good” flag. This
has virtually no effect of the maximum signal pickup, but can have a 
significant effect on the null depth.
1
The thermal output noise voltage en for a loop is
en = √(4kTRB)
where k (1.37 x 10^–23) is Boltzman's constant, T is the absolute temperature 
(taken as 290), (Belrose said:) R is
the resistive component of the input impedance, (but also according to 
Belrose:) R = 2πfL where L is the loop
inductance in Henrys, and B is the receiver bandwidth in Hertz. When the loop 
is rotated so that the signal is
maximum, the signal to noise ratio is
SNR = es/en = [2πA Es /λ]/√(4kTRB) = [66Af/√(LB)]Es .
The point of this formula is that the sensitivity of small loop antennas can be 
limited by internally generated
thermal noise which is a characteristic of the loop itself. Even amplifying the 
loop output with the lowest noise
figure preamp available may not improve the loop sensitivity if man made noise 
drops low enough.
Notice that on the one hand Belrose said R is the resistive component of the 
input impedance, but on the other
hand R = 2πL. Well never mind. Based on personal on hands experience building 
small loops, I believe R =
2πL is approximately correct. What I believe Belrose meant is that R is the 
magnitude of the output impedance.
For a flag antenna rotated so the the signal is maximum, the signal to noise 
ratio is
SNR = es/en = 2[2πA Es/λ]/√(4kT√((2πfL)^2 + (Rflag)^2)B) = [322Af/√(√((2πfL)^2 
+ (Rflag)^2)B)]Es .
Now let us calculate a SNR. Consider a flag 15' by 15' with inductance 24 μH at 
1.0 MHz with 910 ohm flag
resistor, and a bandwidth of B = 6000 Hz. Then A = 20.9 square meters and SNR = 
2.86x10^6 Es . If Es is in
microvolts, the the SNR formula becomes
SNR = 2.9 Es .
Any phased array has loss (or in some cases gain) due to the phase difference 
of the signals from the two
antennas which are combined to produce the nulls. This loss (or gain) depends 
on (1) the separation of the two
antennas, (2) the arrival angle of the signal, and (3) the method used to phase 
the two flags. Let φ be the phase
difference for a signal arriving at the two antennas. It can be shown by 
integrating the difference of the squares
of the respective cosine functions that the amplitude A of the RMS voltage 
output of the combiner given RMS
inputs with amplitudes e is equal to to e√(1 – COS( φ)) where e is the 
amplitude of the RMS signal, in other
words,
A= 1
2π∫
0
2π
2 e2cost−costφ2dt=e21−cosφ
The gain or loss for a signal passing through the combiner due to their phase 
difference is thus √(1 – COS( φ)).
Let us consider the best case, when the signal arrives from the maximum 
direction. For a spacing s between the
centers of the flags, if the arrival angle is α, then the distance d which 
determines the phase difference between
the two signals is d = s COS(α). If s is given in feet, then the conversion of 
d to meters is d = s COS(α)/3.28.
The reciprocal of the velocity of light 1/2.99x10^8 = 3.34 nS/meter is the time 
delay per meter of light (or radio
waves) in air. So the phase difference of the two signals above in terms of 
time is T = 3.34 s COS(α)/3.28 nS
when s is in meters. The phase difference in degrees is thus φ = 0.36Tf = 0.36 
f x 3.34 s COS(α)/3.28 where f is
the frequency of the signals in MHz. If additional delay T' is added (phase 
shift to generate nulls or to adjust the
reception pattern), then the phase difference is φ = 0.36(T + T')f = 0.36f(T' + 
3.34 s COS(α)/3.28) . If the
additional delay is implemented with a length of coax L feet long with velocity 
factor VF, then the phase delay is
φ = 0.37f(L/VF + s COS(α))
where f is the frequency of the signal in MHz, s is in feet, L is in feet, and 
α is the arrival angle.
2
In the case of the flag array above in the maximum direction there are two 
sources of delay, namely 60.6 feet of
coax with velocity factor 0.70, and 100 feet of spacing between the two flag 
antennas. The phase delay at 1.0
MHz for a 30 degree arrival angle is thus
φ = 0.37 x 1.0 x (60.6/0.70 + 100 COS(30)) = 64.1 degrees.
Thus the signal loss in the maximum direction at 30 degree arrival angle due to 
spacing and the phaser is
√(1 – COS( 64.1)) = 0.75 or 20 log(0.75/2) = –8.5 dB.
Now comes the interesting part. What happens when we phase the WF array with 
dimensions and spacing given
above? The flag thermal noise output doubles (two flags), and the flag signal 
output decreases (due to spacing
and phaser loss), so the SNR is degraded by 14.5 dB to
SNR = 0.55 Es .
So a signal of 1.8 microvolts per meter is equivalent to the thermal noise 
floor of the flag array.
On some occasions, when man made noise drops to very low levels at my location, 
it appeared to fall below the
thermal noise floor of the WF array. By that I mean that the characteristic 
“sharp” man made noise changed
character to a “smooth” hiss. To determine whether this was the case, I 
measured the man made noise at my
location for one of these low noise events at 1.83 MHz.
To measure man made noise at my location I converted one of the flags of my MW 
flag array to a loop. The
loop was 15' by 15', or 20.9 square meters. I used my R-390A whose carrier (S) 
meter indicates signals as low
as –127 dBm. The meter indication was 4 dB. Then I used an HP-8540B signal 
generator to determine the dBm
value for 4 dB on the R-390A meter. It was –122 dBm. Now the fun begins. The 
RDF of a loop for an arrival
angle of 20 degrees (the estimated wave tilt of
man made noise at 1.83 MHz) was 4 dB. So now
man made noise after factoring out the loop
directionality was estimated as –118 dBm. Field
strength is open circuit voltage equivalent, which
gives us –112 dBm. I measured MM noise on the
R-390A with a 6 kHz BW. The conversion to
500 Hz is –10 log(6000/500) = –10.8, which
gives us –122.8 or –123 dBm. The conversion to
500 Hz was necessary in order to be consistent
with the SNR above which was calculated for a
500 Hz BW. The loop equation is es = 2πAEs
/lambda = 0.41 Es, and 20 log(0.41) = –7.7,
rounded off to - 8, so we have -115 dBm, or 0.40
microvolts per meter for my lowest levels of man
made noise at 1.83 MHz in a 500 Hz bandwidth.
This seemed impossibly low to me until I came
across the the ITU graph at right. Man made
noise at quiet rural locations may be even lower
than 0.40 microvolts per meter at 1.83 MHz. But what about the MW band? From 
the CCIR Report 322 we
find that the man made noise field strength on the average is about 10 dB 
higher at 1.0 MHz than 1.83 MHz,
which would make it 1.26 microvolts per meter at 1.0 MHz. Another 4 dB is added 
because of impedance
mismatch between the R-390A and the loop, which brings man made noise up to 2.0 
microvolts per meter at 1.0
MHz. The RDF of one of these flags is about 7 dB, which lowers the man made 
noise to 0.89 microvolts per
meter. Observations in the 160 meter band do not seem to agree exactly with 
this analysis because flag thermal
noise has never been heard on the MW flag array. But it would not surprise me 
at all if the flag array thermal
noise floor were only a few dB below received minimum daytime man made noise 
and that measurement error
(for example, calibration of my HP 8640B) accounts for the difference between 
measurement and theory. Also,
observations with a flag array having flag areas half the size of the MW flag 
elements in the 160 meter band do
confirm the signal to noise ratio formula; in this case, flag thermal noise 
does dominate minimum daytime man
made noise at my location (0.40 microvolts per meter field strength measured as 
described above.




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