The plate load impedance depends roughly on the possible anode voltage
swing, not supply voltage, and on the mode (conduction angle) the tube is
biased for. The tube can´t be driven to zero volts on the anode and factor
1,8 is good for class B only.
I would expect tube Z therefore below 2k ohms in that example.
Best is to use the free Eimac "tube performance computer" to do the
calculations.
73
Peter
-----Original Message-----
From: amps-bounces@contesting.com [mailto:amps-bounces@contesting.com] On
Behalf Of KB0NLY
The plate load impedance of your amplifier is expressed approximately as:
[(plate voltage in volts) divided by (1.8 times the plate current in
amps)].""
For me that would be 2400 plate volts and 600 ma of plate current max, this
works out to 2222 ohms.
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