"If my memory is correct the 0.8 ohm or whatever is part of the metering
circuitry, not a glitch resistor"
Glitch in the memory banks, Barry. Drake used a .82 ohm 2 watt resistor in
series with the high voltage lead. It was desgined to act as a fuse. The
problem is that if you are driving the amp with 100 watts and the "fuse"
blows, then the grid is dissipating full power. The impedance may change
somewhat so that the driver will foldback, thus saving the grids - but I
would not depend upon it. If you are using tubes with fragile grids, the
grid then becomes the fuse.
73, Colin K7FM
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