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Re: [Amps] Measuring RF Power

To: garyschafer@comcast.net
Subject: Re: [Amps] Measuring RF Power
From: David Kirkby <david.kirkby@onetel.net>
Date: Sat, 26 Mar 2005 01:36:19 +0000
List-post: <mailto:amps@contesting.com>
Gary Schafer wrote:

>>Average power is not a measure of heating ability.  RMS power is a 
>>measure of heating ability.
>>cr
>>    
>>
>
>That's a common misconception.
>
I agree with you Gary (not specifically that its a common 
misconception), but that RMS power is not the same as average power for 
a sinusoidal voltage applies to a resistor.

For 1V peak voltage and 1 Ohm.

RMS power=sqrt(3/2)/2 W
mean power = 1/2.  W

So they differ by a factor sqrt(3/2) or 1.2247.

>You can not find RMS power by multiplying RMS voltage by RMS current. 
>That gives average power.
>
Yes, agree with you there too.

>If you square RMS voltage and divide by resistance that gives average power.
>
Yep, I agree there too.

>If you square RMS current and multiply by resistance that gives average 
>power.
>
Yep, I agree on that one too.

I'd never really thought about RMS power, as it does not seem a 
particulary useful thing, but if you work out the maths, it is indeed 
not the same as average power for a sine wave voltage waveform.

I think for a square wave they would be the same, but not for a 
sinusoidal voltage (and hence current) waveform.
-- 

Dr. David Kirkby, 
G8WRB

Please check out http://www.g8wrb.org/ 
of if you live in Essex http://www.southminster-branch-line.org.uk/



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