PS, the average power of a 1V peak sine wave across 1 Ohms is 1/2 W, as
we all know.
You can demonstrate mathematically. Just integrate the shape of the
power waveform (which is sin^2) over some integer multiples of the cycle.
In[2]:= Integrate[ Sin[x]^2,{x,0,2 Pi}] / (2 Pi)
1
Out[2]= -
2
But the RMS is *not* 1/2 W, as I have demonstrated.
RMS power is *not* average Power for a sinusoidal voltage waveform.
If you insist on disagreeing Rich, please substantiate it.
--
Dr. David Kirkby,
G8WRB
Please check out http://www.g8wrb.org/
of if you live in Essex http://www.southminster-branch-line.org.uk/
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