jeff millar wrote:
>
> This is a ripple calculation based on the basic capacitor formula
>
> I = C * dV / dT
>
> Let's say you want 3% ripple at 4 KV...that's 120V. The capacitor charges
> on each line peak, twice in each 60 Hz cycle, or 8.3 msec. Rearranging
>
> C = I * dT / dV
>
> Plugging in
>
> C = 0.5A * 8.3 ms / 120V = 35 uFd
>
> jeff, wa1hco
I think you will find the solution is not quite as easy as that - it
depends on type of rectification used - half wave, full wave bridge,
full wave two diodes, 3 phase .... There's a classic paper on this
published many years ago - I'm sure a search on Google will find it.
Dr. David Kirkby PhD,
Senior Research Fellow,
Department of Medical Physics,
University College London,
11-20 Capper St, London, WC1E 6JA.
Tel: 020 7679 6408 Fax: 020 7679 6269
Internal telephone: ext 46408
e-mail davek@medphys.ucl.ac.uk
Web page: http://www.medphys.ucl.ac.uk/~davek
|