Maybe I have the math wrong....
E=sqrt(P*R)
so
P == 100
R == 50
then E = 70.7106 or approx 100V Peak
Or am I wayyyyyyyyyyyyyy off?
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Microsoft is the question and the answer is NO!
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--- On Fri 11/22, Steve Katz wrote:
From: Steve Katz [mailto: stevek@jmr.com]
To: ad5gb@myway.com, amps@contesting.com
To: <amps@contesting.com>
Date: Fri, 22 Nov 2002 07:56:44 -0800
Subject: RE: [Amps] Passive grid: How to calculate..... ?
>
>
> > I'm also assuming 100V pk for a 100W transciever. ( someone please
> > correct me if I'm way out in orbit somewhere!!! )
> >
> [Steve Katz] Where'd the 100V come from? E = SQRT P*R. -WB2WIK/6
>
> > Many thanks!
> >
> >
> > --
> > Microsoft is NOT the answer
> > Microsoft is the question and the answer is NO!
> >
> > Proud to be 100% Microsoft Free
> >
> > _______________________________________________
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> > http://lists.contesting.com/mailman/listinfo/amps
>
_______________________________________________
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