Hung up trying to calculate the Q of a coil I want to
build. It will be 2 inches in diameter with 26 turns
of #10 wire. The length is 5.3 inches. 4.9 Turns per
inch. HAMCALC computes this at 11uh of inductance.
If I got it right
Inductive Reactance of this coil on 10 meters=
2*3.14*29000000*.000011 or 2003 ohms
Q of this coil should be the Inductive Reactance
divided by the internal resistance of the coil's wire
(factoring in the RF). This is where I got bogged
down. Couldn't come up with an appropiate number.
Where am I going wrong?
73,
Bill
=====
Bill Smith KO4NR
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