Good question Firson.
First, when you place a load on this power supply, the output voltage will
drop a bit so that the final AC "power" won't be 2550 x 0.5 watts, but will
be perhaps 2200 x 0.5 watts.
Second, the 0.5 amp rating of the transformer is the maximum continuous
current rating. For intermittent service (like an amateur amplifier) you
will be able to safely draw more power from the transformer as long as the
maximum temperature rise for the transformer is not exceeded. A good
example of this is the Heath SB-220 : it has a transformer rated for 600 or
700 watts yet the amplifer produces 900 - 1300 watts across the various
amateur bands. The Heath transformer is "overloaded", but this is
acceptable because of the low duty cycle for SSB and CW. This same
situation is found in many of the amateur amps on the market.
That's it in a nutshell.
Phil
At 12:52 PM 7/31/2000 JAVT, you wrote:
>
>I have Transformer 1880 volt with max current 0.5A, When we calculate max
>output power that is 1880 x 0.5 = 940 watt AC. When I make HV Power supply
>with bridge diode and capasitor. The DC output will be 2500 volt DC and 0.5
>max current. Total output power is 2500 x 0.5 = 1250 watt DC. I am confused
>with watt terminology here, where 1250 minus 940 = 310 watt... Where does
>this 310 watt come from, Could anybody explain me why ???....
>
>de Firson YD1BIH
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