On Wed, 4 Aug 1999 04:39:07 -0700 Rich Measures <measures@vc.net> writes:
>? RL = 2000 ohms. R out equals 50-ohms. Freq = 7.00MHz. Q = 10
>Therefore, C1 = 2000 ohms/10 = 200 ohms. From calculation, C1 = 114pF,
>C2 = 562pF, L = 5.06uH. Since C1 is effectively in series with C2,
>C-net = 94.8pF. The resonant freq. of 5.06uH in parallel with 94.8pF is
>7.266MHz.
>
>- cheers, Tom
>
Hi Rich,
You didn't detail the formulas you used for L & C2 but, from your C1
calculation, I note that you are using the classic "time-dishonored"
approximation which is close enough for amateur work (as long as the Q is
reasonably high) though, certainly not mathematically precise to support
the argument du jour. :-)
73,
Marv WC6W
*
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