| >Jon Ogden wrote:
>>
>>How can a series resistance of 100 Ohms or so be greater than the K-Ohm 
>>impedance of the anode circuit?
>>
>A 100-ohm resistor can LOOK like 1K to the tube, because of the
>impedance-transforming properties of the inductances in the circuit. 
>
>Pulling some example figures out of the air, consider a suppressor that
>consists of 100 ohm resistor paralleled by 100nH. In series with that is
>say 200nH of connecting lead inductance between the tube and the pi-
>tank. At 100MHz, this network transforms into 1058 ohms in parallel with
>279nH.
>
Out of the air, indeed.  .  How about going through the calculations, Mr 
White?  
>That's where your K-ohm comes from...  and yes, you ARE supposed to ask
>that question!
 
Rich...
R. L. Measures, 805-386-3734, AG6K   
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