>Someone said:
>>
>>>Cathode temperature would drop at the nearly the same rate as it
>>>takes to rise. If the line totally removed voltage for ten seconds,
>>>it would only require a ten second warm up to be back at full
>>>temperature.
><><><><><><><><><><><><><><><><><><><><><><><><><><><><>
>I don't believe this is correct. Warm-up or down time is like an RC
>time constant curve. When charging a capacitor, the last few percent
>takes much longer than the first few percent. The reverse holds true
>for discharging. When power is removed, the initial drop rate is much
>faster than the later drop rate. Kind of like your bank account - it
>goes out a lot faster than it comes in.
>
So it would seem, Bill.
- Rich -
R. L. Measures, 805-386-3734, AG6K
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