This is handy
http://www.csgnetwork.com/righttricalc.html
----- Original Message -----
From: "Dave Hachadorian" <k6ll@arrl.net>
To: "Towertalk reflector" <towertalk@contesting.com>
Sent: Saturday, 28 August, 2010 4:35 PM
Subject: Re: [TowerTalk] Guy wire height from anchor to tower
> ------------------------------------
> From: "Mac English" <km9zkb9mdl@yahoo.com>
> Sent: Saturday, August 28, 2010 12:10 PM
> To: <towertalk@contesting.com>
> Subject: [TowerTalk] Guy wire height from anchor to tower
>
>> I would greatly appreciate it if someone could help me figure
>> out how to
>> calculate guy wire height from the guy anchor up towards the
>> tower.
>>
>>
>> My tower height will be at 70 ft. My first set of guy will be
>> at the 32 ft level
>> the second set will be around the 68 ft level. The total
>> distance to each
>> anchor from the base of the tower is 45ft.
>>
>> On one of my anchors is only 14 feet away from my home. The max
>> height on my
>> home where the first set of guys will pass is around 11 feet
>> high. I need to
>> know how high that first set of guys will be at 14 feet from
>> the anchor to the
>> roof where these guys will pass. The length of the guy wire on
>> the first level
>> of guys is 53 feet long from anchor to tower. All anchors will
>> be about 1ft 8in
>> above ground.
>>
>> I am wondering if the first set of guys will be high enough off
>> the ground to
>> clear my home. I have some logistical issues with respect to
>> where I can place
>> the tower & guys on my property because of utilities and the
>> placement of
>> buildings on my property.
>>
>
> For a horizontal distance of 45 feet, the guy wire will rise
> 30.34' (32 - 1.66)
>
> So for every foot of horizontal distance, the wire will rise
> 0.674' (30.34/45)
>
> For a horizontal distance of 14 ft, the guy will rise 9.436'
> (.674 x 14)
>
> Since the guy started at a height of 1.66', it will be at a
> height of 11.096' (9.436 + 1.66) (ignoring sag) above ground when
> it passes the
> top of your house. That's too close. You could make the anchor
> higher, guy higher on the tower, guy further out, or put the
> anchor for the lower guy on the other side of the house, if
> any of that is possible.
>
>
>> Plus while we are at it I will be digging a 2x2x4 ft hole for
>> the base of the
>> tower. The anchors will be 5ft deep by a 2 ft wide undisturbed
>> hole. I need to
>> figure out how much concrete will go in each hole and how much
>> concrete will it
>> take to fill the tower base.
>
> You should have about 2" of concrete above grade for the tower
> base.
> 2 x 2 x 4.166 = 16.664 cu ft = 0.62 cu yd
>
> I guess you are using raised anchors, so the concrete should be
> 2" above grade here also. I think you meant a 2x2x5' square hole.
> 2 x 2 x 5.166 = 20.664 cu ft = 0.765 cu yd
>
> If you meant a 2' diameter round hole 5' deep, it would be
> 3.1416 x 5.166 = 16.23 cu ft = 0.6 cu yd
>
> Dave Hachadorian, K6LL
> Big Bear Lake, CA
>
>
>
>
> _______________________________________________
>
>
>
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