With r people present, the probability that no one shares a birthday is
(1-1/365)(1-2/365)(1-3/365) ... (1-(r-1)/365)
This works out to around 0.5 for 23 people. (assuming rates are the
same for all days, and 365 days a year)
Raj, N2RD
On Friday, August 1, 2003, at 11:38 AM, K4SB wrote:
> Robert McGwier wrote:
> snipped
>> committees had better go have a long hard look at the classic
>> probability first year section canard called "the birthday
>> problem".
>
> For those not familiar with the "birthday problem", I seem to
> remember that if 27 people are present, the odds are better than 90%.
>
> Been a long time though...
>
> And never bet against professors!
> ):>
> Ed
--
Rajiv Dewan, N2RD
FN13fc
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