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Total 9 documents matching your query.

1. [TowerTalk] anchor points (score: 1): Author: mainhart@juno.com (Rick Mainhart); Date: Wed, 2 Jul 1997 20:49:43 -0400; aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaagh That's the LAST time I try to do any thinking after working overtime fixing someone else's air conditioning. 73, Slightly embarrassed, Rick, WB3EXR On Mon, 30; /archives//html/Towertalk/1997-07/msg00110.html (9,046 bytes)
2. [TowerTalk] anchor points (score: 1): Author: w7ni@teleport.com (Stan Griffiths); Date: Thu, 3 Jul 1997 22:04:51 -0700 (PDT); There is more to anchor design than just using the same amount of concrete that Rohn does. The SHAPE of the concrete piece undergound has a LOT to do with how much it will hold. It isn't just the co; /archives//html/Towertalk/1997-07/msg00157.html (8,143 bytes)
3. [TowerTalk] anchor points (score: 1): Author: k1my@nlis.net (Bruce Makas); Date: Sun, 29 Jun 1997 15:50:15 -0400; It seems to me that it would be easier to drill round holes with a tractor powered post hole digger for the guy wire anchor points than try and dig them by hand. If I use the same amount of concrete; /archives//html/Towertalk/1997-06/msg00980.html (8,764 bytes)
4. [TowerTalk] anchor points (score: 1): Author: mainhart@juno.com (Rick Mainhart); Date: Sun, 29 Jun 1997 21:28:00 -0400; Ah ... a cubic yard is 3 x 3 x 3 or 27 cubic feet. 27*.67= 18.09 cubic feet required (using your figure) 18.09/3.14=5.76 feet depth required for 1 foot diameter; 18.09/6.28=2.88 feet depth required f; /archives//html/Towertalk/1997-06/msg00990.html (8,166 bytes)
5. [TowerTalk] anchor points (score: 1): Author: seay@Alaska.NET (Jan & Del Seay); Date: Sun, 29 Jun 1997 19:10:43 -0800 (AKDT); Remember the goal is not to provide x-lbs of concrete to hold the load, but to provide a device that requires movement of x-yards of undisturbed earth. A flat sided device will require more earth to; /archives//html/Towertalk/1997-06/msg00991.html (9,637 bytes)
6. [TowerTalk] anchor points (score: 1): Author: dietz@texas.net (Chuck Dietz); Date: Mon, 30 Jun 1997 07:37:48 -0500; I agree, however, I would drill with the tractor and then square the holes with a "sharpshooter" shovel and hand post hole diggers... Chuck, KE5FI -- FAQ on WWW: http://www.contesting.com/towertalkfa; /archives//html/Towertalk/1997-06/msg00995.html (7,711 bytes)
7. [TowerTalk] anchor points (score: 1): Author: ku7y@sage.dri.edu (Monte Stark); Date: Mon, 30 Jun 1997 07:20:50 -0700 (PDT); Hi Chuck, Keep in mind that you could use the power auger to dig about 3 or 4 holes in a row and then clean them out with a shovel. This would give you the trench you need for the anchor, use power t; /archives//html/Towertalk/1997-06/msg00999.html (8,422 bytes)
8. [TowerTalk] anchor points (score: 1): Author: aa4lr@radio.org (Bill Coleman AA4LR); Date: Mon, 30 Jun 97 17:52:20 -0400; Hmm. My back of the envelope computation says something isn't right. If you double the diameter, that quadruples the volume per foot of height. If 5.76 feet is right for a 1 foot hole, then a two foo; /archives//html/Towertalk/1997-06/msg01015.html (8,463 bytes)
9. [TowerTalk] anchor points (score: 1): Author: kurscj@oampc12.csg.mot.com (Chad Kurszewski WE9V); Date: Mon, 30 Jun 1997 17:07:42 -0500; Well, maybe it should be, but it isn't. Let's try pi*r^2*h (no 2* in there) Area of a circle is pi*r^2, times the height is volume. Nor with that math. :) p.s. a 1 foot diameter hole would need to b; /archives//html/Towertalk/1997-06/msg01019.html (8,661 bytes)

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