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1. [Amps] Again (score: 1): Author: "Mike(W5UC) & Kathy(K5MWH)" <w5uc@cox.net>; Date: Sun, 2 Jul 2006 06:30:57 -0500; There clearly are individuals on this reflector who are more knowledgeable than me, so I will ask this question again, but in a differently worded form. How does the impedance of the PA tank affect t; /archives//html/Amps/2006-07/msg00042.html (6,812 bytes)
2. Re: [Amps] Again (score: 1): Author: "Michael Tope" <W4EF@dellroy.com>; Date: Sun, 2 Jul 2006 05:27:14 -0700; Hi Mike, In principle for a given operating class (A, AB1, AB2, C), matching the load impedance presented by the tank circuit to the output impedance of the tube provides maximum available output pow; /archives//html/Amps/2006-07/msg00044.html (8,795 bytes)
3. Re: [Amps] again (score: 1): Author: "Roy Koeppe" <royanjoy@ncn.net>; Date: Sun, 2 Jul 2006 09:32:01 -0500; This question, "There clearly are individuals on this reflector who are more knowledgeable than me, so I will ask this question again, but in a differently worded form. How does the impedance of the; /archives//html/Amps/2006-07/msg00049.html (7,525 bytes)
4. Re: [Amps] again (score: 1): Author: "Mike(W5UC) & Kathy(K5MWH)" <w5uc@cox.net>; Date: Sun, 2 Jul 2006 10:22:29 -0500; Roy, I agree. This came up because I found a schematic for a pair of Gi-7b's and was kinda using it as a guide. Meanwhile back at the ranch, I looked up the formulas for calculating the values in a p; /archives//html/Amps/2006-07/msg00054.html (9,248 bytes)
5. Re: [Amps] again (score: 1): Author: "Larry Carman" <lncarman@swbell.net>; Date: Sun, 2 Jul 2006 13:24:03 -0500; Mike, I have an on-line calculator for pi & pi-L at this link http://www.pinebeetle.net/amplifier_main.html . These calculations are based on the formulas from ARRL handbook. Regards, Larry N5BIP Mea; /archives//html/Amps/2006-07/msg00063.html (7,642 bytes)
6. Re: [Amps] again (score: 1): Author: Peter Chadwick <g3rzp@g3rzp.wanadoo.co.uk>; Date: Mon, 3 Jul 2006 10:31:13 +0200 (CEST); the load and for maximum efficiency all at the same time < This gets perilously close to igniting that argument about whether or not you provide a conjugate match to the tube. Since most linear amps; /archives//html/Amps/2006-07/msg00077.html (7,872 bytes)
7. Re: [Amps] again (score: 1): Author: "Tom W8JI" <w8ji@w8ji.com>; Date: Mon, 3 Jul 2006 06:30:48 -0400; The conjugate match theorem tells us nothing about what goes on inside the source, never has...never will. The rules or limits of the theorem even state that. Anyone who thinks a match to the source; /archives//html/Amps/2006-07/msg00082.html (7,985 bytes)
8. Re: [Amps] again (score: 1): Author: "Tom W8JI" <w8ji@w8ji.com>; Date: Mon, 3 Jul 2006 08:22:40 -0400; Mike, Looking back at the posts it *seems to me* you are thinking the design of the tank sets the load Z at the tube. That's what I think is going on, so I'll answer that way. It really doesn't matt; /archives//html/Amps/2006-07/msg00089.html (11,777 bytes)
9. Re: [Amps] again (score: 1): Author: R L Measures <r@somis.org>; Date: Mon, 3 Jul 2006 04:27:45 -0700; In one of my electronics classes, the professor proved conclusively that maximum power transfer occurred at 50% efficiency, but I see amplifiers that exhibit 60% efficiency. Please explain why, Tom.; /archives//html/Amps/2006-07/msg00095.html (8,846 bytes)
10. Re: [Amps] again (score: 1): Author: "Joe Subich, W4TV" <w4tv@subich.com>; Date: Mon, 3 Jul 2006 10:20:28 -0400; Although I have not done the mathematics, since power transfer occurs at less than 360 degrees when the amplifier is operated in other than class A service, why don't you try doing an integration of; /archives//html/Amps/2006-07/msg00099.html (8,896 bytes)

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