- 1. [Amps] HV Divider, Problem Solved (score: 1)
- Author: "KB0NLY" <kb0nly@mchsi.com>
- Date: Sun, 1 Mar 2009 14:15:24 -0600
- Well i don't know how this amp was working before i started the modifications but i pulled the resistor from B- to chassis ground, at an AMPS member suggestion, to measure it, it was open! So i grabb
- /archives//html/Amps/2009-03/msg00023.html (7,988 bytes)
- 2. Re: [Amps] HV Divider, Problem Solved (score: 1)
- Author: "Bob Maser" <bmaser@tampabay.rr.com>
- Date: Sun, 01 Mar 2009 12:25:09 -0800
- I gave you the answer in my previous. Read about measuring voltage using a ammeter, which is what you are really doing. Find a 1ma full scale AMMETER and use 5 megohms in the meter multiplier string.
- /archives//html/Amps/2009-03/msg00024.html (9,109 bytes)
- 3. Re: [Amps] HV Divider, Problem Solved (score: 1)
- Author: "KB0NLY" <kb0nly@mchsi.com>
- Date: Sun, 1 Mar 2009 14:35:05 -0600
- The handbook is sitting right next to me and I still don't see the math I'm looking for. I need the equation that I can fill in to determine the high voltage when I know the value of the string and t
- /archives//html/Amps/2009-03/msg00027.html (10,762 bytes)
- 4. Re: [Amps] HV Divider, Problem Solved (score: 1)
- Author: "Gary Schafer" <garyschafer@comcast.net>
- Date: Sun, 1 Mar 2009 15:48:06 -0500
- Scott, Just ohms law: first you need to find the current thru the whole divider between B+ and ground. E/R = I In this case 10 meg + 50K. So then, 2350/10050000 = .00023 amps. Then use IxR = V to fin
- /archives//html/Amps/2009-03/msg00031.html (12,743 bytes)
- 5. Re: [Amps] HV Divider, Problem Solved (score: 1)
- Author: "KB0NLY" <kb0nly@mchsi.com>
- Date: Sun, 1 Mar 2009 14:52:13 -0600
- Gary, Thank you for further explaining that, this is all going into my notebook, I would say my brain but my memory is pretty lacking! At least with it written down in my handy dandy notebook (Blue's
- /archives//html/Amps/2009-03/msg00032.html (12,906 bytes)
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