Google is amazing:
--------------------------
Suppose the reel has hub diameter Di, outside diameter Do, and width
W. Then the volume of wire on it is
V = pi(Do^2 - Di^2)W/4
Suppose you have a wire with length L and square cross-section with
side Dw (the diameter of the wire). Its volume is
V = LDw^2
Setting these equal, we get
LDw^2 = pi(Do^2 - Di^2)W/4
and we can solve to find
L = pi(Do^2 - Di^2)W/(4Dw^2)-------------------------------This
formula assumes zero airspace in the windings, so it should overstate
the length somewhat.Dave Hachadorian, K6LLYuma, AZ
_______________________________________________
See: http://www.mscomputer.com for "Self Supporting Towers", "Wireless Weather
Stations", and lot's more. Call Toll Free, 1-800-333-9041 with any questions
and ask for Sherman, W2FLA.
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